## Hard question

**Moderator:** Moderators

### Hard question

Ok, here it is (It's math)

A guys asking his classs if they wanted a pizza Party. There are 2 plans to determane if they get a party. Which plan should the students choose:

Plan A:

If the Sum is even, there will be a pizza party. If the sum is odd, there will not be a Pizza party.

Plan B:

If the product is even, there will be a pizza party. If the product is odd, there will not be a pizza party.

I think it's Plan B, but how do you figure this out!? My parents don't know, and my friends have no idea either!

A guys asking his classs if they wanted a pizza Party. There are 2 plans to determane if they get a party. Which plan should the students choose:

Plan A:

If the Sum is even, there will be a pizza party. If the sum is odd, there will not be a Pizza party.

Plan B:

If the product is even, there will be a pizza party. If the product is odd, there will not be a pizza party.

I think it's Plan B, but how do you figure this out!? My parents don't know, and my friends have no idea either!

- geekbait111
**Posts:**413**Joined:**Tue Feb 14, 2006 9:15 am**Location:**hiding your attic...waiting

I think this might be an algebra elimination question, I'll tell you the answer in (possibly) several min. We just learned it this year

edit: If it isn't elimination/anything I know, I can't tell you . But I'm not sure...

edit: If it isn't elimination/anything I know, I can't tell you . But I'm not sure...

Last edited by geekbait111 on Tue Mar 14, 2006 7:43 pm, edited 1 time in total.

- MilkMonster
**Posts:**470**Joined:**Sat Aug 06, 2005 2:52 pm**Location:**A stupid place in NC-
**Contact:**

- geekbait111
**Posts:**413**Joined:**Tue Feb 14, 2006 9:15 am**Location:**hiding your attic...waiting

- geekbait111
**Posts:**413**Joined:**Tue Feb 14, 2006 9:15 am**Location:**hiding your attic...waiting

is this a school question? If so, what are you learning currently?

edit: x=# y=other #, z=pizza party, a =no pizza party... so plan A) x+y=z or x+y=a

plan B) xy=z or xy=a

edit: x=# y=other #, z=pizza party, a =no pizza party... so plan A) x+y=z or x+y=a

plan B) xy=z or xy=a

Last edited by geekbait111 on Tue Mar 14, 2006 7:50 pm, edited 1 time in total.

It's plan B.

if you do plan B then you have a 3/4 chance you'll get a party:

odd x even = even

even x odd = even

even x even = even

od x odd = odd

if you do plan B then you have a 3/4 chance you'll get a party:

odd x even = even

even x odd = even

even x even = even

od x odd = odd

Last edited by daguuy on Tue Mar 14, 2006 7:54 pm, edited 2 times in total.

- geekbait111
**Posts:**413**Joined:**Tue Feb 14, 2006 9:15 am**Location:**hiding your attic...waiting

ya, B is better... find a pattern. example...

A) 1+1=2

1+2=3, 1+3=4 etc...

2+1=3,2+2=4

Therefore you have 1/2 chance.

plan B)

1*1=1

1*2=2

so 1/2 chance there BUT...

every odd number =1/2 chance odd, 1/2 chance even (do the math, you'll find out I'm correct)

And...

every even # *any number =even

therefore the chance is 1/1 or 1

so (1+1/2)/2 (a.k.a the mean) is .75

Summary:

plan A gives 1/2 chance of pizza party

plan B gives 3/4 chance of pizza party

And unless someone is allergic to pizza or very obeise, plan B is the better one .

A) 1+1=2

1+2=3, 1+3=4 etc...

2+1=3,2+2=4

Therefore you have 1/2 chance.

plan B)

1*1=1

1*2=2

so 1/2 chance there BUT...

every odd number =1/2 chance odd, 1/2 chance even (do the math, you'll find out I'm correct)

And...

every even # *any number =even

therefore the chance is 1/1 or 1

so (1+1/2)/2 (a.k.a the mean) is .75

Summary:

plan A gives 1/2 chance of pizza party

plan B gives 3/4 chance of pizza party

And unless someone is allergic to pizza or very obeise, plan B is the better one .

- Sir Games-A-Lot
**Posts:**710**Joined:**Thu Apr 07, 2005 7:25 am**Location:**Sitting around a table wishing the king would get IBM Consultants

You must have misread the question or maybe it's a typo because this problem usually involves a pair of numbered cubes (AKA six sided dice).

See: LINK with explanation. (hope this dosen't constitute cheating)

1 am the Sm4tz, t3h google iz my friendz0r.

See: LINK with explanation. (hope this dosen't constitute cheating)

1 am the Sm4tz, t3h google iz my friendz0r.

<a href="http://www.nerdtests.com/ft_cg.php?im">

<img src="http://www.nerdtests.com/images/ft/cg.php?val=5780" alt="My computer geek score is greater than 83% of all people in the world! How do you compare? Click here to find out!"> </a>

<img src="http://www.nerdtests.com/images/ft/cg.php?val=5780" alt="My computer geek score is greater than 83% of all people in the world! How do you compare? Click here to find out!"> </a>

What he said.daguuy wrote:It's plan B.

if you do plan B then you have a 3/4 chance you'll get a party:

odd x even = even

even x odd = even

even x even = even

od x odd = odd

I presume it's asking what the better chance out of both is.

If the Sum is even, there will be a pizza party. If the sum is odd, there will not be a Pizza party.

One approach:

12 votes yes

8 vote no

**20 vote**

13 vote yes

6 vote no

**19 vote**

2nd approach:

20 classmates :: even, party time!

23 classmates :: odd, no party

Plan A:

50% chance yes.

50% chance no.

Plan B:

75% chance yes.

25% chance no.

Take of it as you will, Plan B is better.

- geekbait111
**Posts:**413**Joined:**Tue Feb 14, 2006 9:15 am**Location:**hiding your attic...waiting