Hard question

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Harshboy
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Hard question

Post by Harshboy » Tue Mar 14, 2006 7:40 pm

Ok, here it is (It's math)

A guys asking his classs if they wanted a pizza Party. There are 2 plans to determane if they get a party. Which plan should the students choose:

Plan A:

If the Sum is even, there will be a pizza party. If the sum is odd, there will not be a Pizza party.

Plan B:

If the product is even, there will be a pizza party. If the product is odd, there will not be a pizza party.


I think it's Plan B, but how do you figure this out!? My parents don't know, and my friends have no idea either!

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geekbait111
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Post by geekbait111 » Tue Mar 14, 2006 7:42 pm

I think this might be an algebra elimination question, I'll tell you the answer in (possibly) several min. :D We just learned it this year
edit: If it isn't elimination/anything I know, I can't tell you :( . But I'm not sure...
Last edited by geekbait111 on Tue Mar 14, 2006 7:43 pm, edited 1 time in total.

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MilkMonster
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Post by MilkMonster » Tue Mar 14, 2006 7:43 pm

Uhh... Plan C, buy a pizza and eat it. :)

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Kurt_
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Post by Kurt_ » Tue Mar 14, 2006 7:44 pm

Well to understand which is better, you have to define what the product and sum is.

Sum is addition/subtraction, and product is multiplication and division, I believe.

But sum and product of what?
Hey, sup?

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geekbait111
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Post by geekbait111 » Tue Mar 14, 2006 7:45 pm

wait, the product and sum of what??? x any y?

Harshboy
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Post by Harshboy » Tue Mar 14, 2006 7:47 pm

the problem doesnt say and values.......so, anyone who can help?

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geekbait111
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Post by geekbait111 » Tue Mar 14, 2006 7:48 pm

is this a school question? If so, what are you learning currently?
edit: x=# y=other #, z=pizza party, a =no pizza party... so plan A) x+y=z or x+y=a
plan B) xy=z or xy=a
Last edited by geekbait111 on Tue Mar 14, 2006 7:50 pm, edited 1 time in total.

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Kurt_
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Post by Kurt_ » Tue Mar 14, 2006 7:49 pm

Well the numbers are the determining factor.

Just flip a coin. 50% chance you're right.
Hey, sup?

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daguuy
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Post by daguuy » Tue Mar 14, 2006 7:53 pm

It's plan B.

if you do plan B then you have a 3/4 chance you'll get a party:
odd x even = even
even x odd = even
even x even = even
od x odd = odd
Last edited by daguuy on Tue Mar 14, 2006 7:54 pm, edited 2 times in total.
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Harshboy
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Post by Harshboy » Tue Mar 14, 2006 7:54 pm

it's PSSA testing prep...and i dont get it!

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Kurt_
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Post by Kurt_ » Tue Mar 14, 2006 7:55 pm

If there's no numbers, then I say this:

[English]
"By Geoo'orge! I think he's go't it! Wot Wot!"
[/English]
Hey, sup?

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geekbait111
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Post by geekbait111 » Tue Mar 14, 2006 7:59 pm

ya, B is better... find a pattern. example...
A) 1+1=2
1+2=3, 1+3=4 etc...
2+1=3,2+2=4
Therefore you have 1/2 chance.
plan B)
1*1=1
1*2=2
so 1/2 chance there BUT...
every odd number =1/2 chance odd, 1/2 chance even (do the math, you'll find out I'm correct)
And...
every even # *any number =even
therefore the chance is 1/1 or 1
so (1+1/2)/2 (a.k.a the mean) is .75
Summary:
plan A gives 1/2 chance of pizza party
plan B gives 3/4 chance of pizza party
And unless someone is allergic to pizza or very obeise, plan B is the better one :D .

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Post by Sir Games-A-Lot » Tue Mar 14, 2006 8:01 pm

You must have misread the question or maybe it's a typo because this problem usually involves a pair of numbered cubes (AKA six sided dice).

See: LINK with explanation. (hope this dosen't constitute cheating)

1 am the Sm4tz, t3h google iz my friendz0r. :P
<a href="http://www.nerdtests.com/ft_cg.php?im">
<img src="http://www.nerdtests.com/images/ft/cg.php?val=5780" alt="My computer geek score is greater than 83% of all people in the world! How do you compare? Click here to find out!"> </a>

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Skyone
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Post by Skyone » Tue Mar 14, 2006 8:02 pm

daguuy wrote:It's plan B.

if you do plan B then you have a 3/4 chance you'll get a party:
odd x even = even
even x odd = even
even x even = even
od x odd = odd
What he said.

I presume it's asking what the better chance out of both is.
If the Sum is even, there will be a pizza party. If the sum is odd, there will not be a Pizza party.

One approach:

12 votes yes
8 vote no

20 vote

13 vote yes
6 vote no

19 vote



2nd approach:

20 classmates :: even, party time!

23 classmates :: odd, no party :(



Plan A:
50% chance yes.
50% chance no.


Plan B:
75% chance yes.
25% chance no.


Take of it as you will, Plan B is better.

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geekbait111
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Post by geekbait111 » Tue Mar 14, 2006 8:04 pm

meow

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