There's four scenarios I can think of that need to be checked. In all of this assume the voltages and resistance levels are correct. Also, the think of the DC Input symbol as a switch that closes the circuit only when it has power.
Switch in 1st position - DC Input has NO power
Switch in 1st position - DC Input HAS power
Switch in 2nd position - DC Input has NO power
Switch in 2nd position - DC Input HAS power
The schematic should work like this:
When the DPDT switch is in the first position, the system draws from battery. If the DC input has power at this point, it will pass through the resistor and trickle charge the batteries.
When the switch is in the second position, the system will draw from the DC Input and trickle charge the batteries. If the DC Input has no power, nothing will happen.
![Image](http://home.earthlink.net/~moose_jr/images/portablen64/N64%20Power%20Schematic.gif)
Tell me what you find. Thanks!